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The length and breadth of a rectangular floor are 16.25 metre and 12.75 metre respectively. Find how many minimum number of square tiles would be required to cover it completely?
Since we require minimum number of square tiles, the size of the tile is given as the H.C.F. Of two sides of the room.
The H.C.F. Of 1625 cm & 1275 cm. is 25 cm. Hence, we get,
Required Number = (1625 × 1275) / (25 × 25) = 3315
The L.C.M. of two number is 60. The numbers are in the ratio 4 : 5. Find the sum of numbers.
Let the numbers be 4x and 5x.
Then, their L.C.M. = 20x.
20x = 60 or x = 3.
The numbers are 12 and 15.
Hence, required sum = (12 + 15) = 27.
The L.C.M. Of 2, 2.7 and 0.09 is:
Given numbers are 2.00, 2.70 and 0.09.
L.C.M. of 200, 270 and 9 is 5400.
L.C.M. Of given numbers = 54.00 = 54
Find the least number which should be added to 2430 so that the sum is exactly divisible by 5, 4 and 2
L.C.M of 5, 4, and 2 = 20. On dividing 2430 by 20, the remainder is 10.
Therefore, number to be added = (20 - 10) = 10
The ratio of two numbers is 4 : 5 and their H.C.F is 4. Find their L.C.M.
H.C.F = x. So, x=4.
So, the numbers are 16 and 20
L.C.M of 16 and 20 = 80.
Complete review of GRE Chemistry with practice questions
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