2) xy ? – y
Statement (2) says that x is
.
Countinue
If xy ?
– y, then x can’t be –1. Is this sufficient to tell
us whether x 3 < x 2 ?
We know that we can answer "Yes" when x is either 3
or –3. We know that x can’t be –1. Are there other cases we need to think
about?
Yes, we need to consider the case where x = 1.
When x = 1, the left side evaluates: 11 = 1 while the
right side evaluates: 
. So, both sides are equal instead of the left side
being greater than the right. That means we can answer the question "No"
for x = 1. Since we answered "Yes" for x = 3 (and
–3), this statement is insufficient.
So now we need to consider the two statements together.
Countinue
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