Solve the question on your notebook and check it by clicking (Answer and Explanation) below question.
The L.C.M. of two numbers is 14560 and their H.C.F. is 13. If one of them is 416, the other is
if A and B are two numbers
A × B = HCF of A and B × LCM of A and B
416 × number = 14560 × 13
Number = 445
22×32×72 , 2×34×7
HCF is Highest common factor, so we need to get the
common highest factors among given values. So we got
2 × 3 × 3 × 7
Find the HCF of 54, 288, 360
Lets solve this question by factorization method.
18=2×32,288=25×32,360=23×32×5
So HCF will be minimum term present in all three, i.e.
2 × 32 = 18
Reduce
We can do it easily by in two steps
Step 1: We get the HCF of 368 and 575 which is 23
Step 2: Divide both by 23, we will get the answer 16/25
HCF of 803 and 876 is 73, Divide both by 73,
We get the answer 11/12.
Prepare ECAT with practice questions for admissions in Engineering colleges
Join Pakistan Air Force as a Cadet. Learn all about joining
How to prepare for SAT Reasoning paper-base and online
Admission detail for admission in P ...
A famous name incolleges in Lahore ...
Get school education in Australia. ...
How you can get Visa to study in Au ...
A comprehensive list of popular sch ...
Find comprehensive list of major sc ...
Best schools in the cities of Londo ...
Find school in your location. List ...
Learn how to deal Analytical Reason ...
Learn to manage time on Analytical ...