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Two pipes A and B can fill a tank in 6 hours and 4 hours respectively. If they are opened on alternate hours and if pipe A is opened first, in how many hours, the tank shall be full ?
(A+B)'s 2 hour's work when opened =
Now, its A turn in 5th hour
1/6 work will be done by A in 1 hour
Total time = 4 + 1 = 5 hours
There are two pipes which are functioning simultaneouly to fill a tank in 12 hours, if one pipe fills the tank 10 hours faster than other then how many hours second pipe will take to fill the tank ?
Lets suppose tank got filled by first pipe in X hours,
So, second pipe will fill the tank in X + 10 hours.
If one is added to the numerator of the fraction it becomes one. If one is added to the denominator of the fraction it becomes 1/2. The fraction is?
Let the fraction be x/y.
=> (x+1)/y = 1
=> 2x = (y+1)—(2)
=>Equating (1) and (2)
=> x+1 = 2x-1
=>x=2
Substituting the value of x in (1)
=>y=3
=>2/3
If x + 5y = 16 and x= -3y, then y =
Which of the following fraction is greater than 2/3 and less than 4/5 ?
1/2 = 0.5, 2/3 = 0.66, 4/5 = 0.8, 9/10 = 0.9, 3/4 = 0.75, 5/6 = 0.833,
Clearly, 0.8 lies between 0.75 and 0.833
3/4 lies between 2/3 and 4/5
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