Solve the question on your notebook and check it by clicking (Answer and Explanation) below question.
A person travels from P to Q at a speed of 40 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips ?
Speed while going = 40 km/hr
Speed while returning = 150% of 40 = 60 km/hr
Average speed =
The distance between two cities A and B is 330 Km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m and travels towards A at 75 Km/hr. At what time do they meet?
Suppose they meet x hrs after 8 a.m.
then
(Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs]
= 330
So, 60x+75(x-1) = 330
x=3.
So,they meet at (8+3). i.e 11a.m.
A man in a train notices that he can count 41 telephone posts in one minute. If they are known to be 50 metres apart, then at what speed is the train travelling?
Number of gaps between 41 poles = 40
So total distance between 41 poles = 40×50
= 2000 meter = 2 km
In 1 minute train is moving 2 km/minute.
Speed in hour = 2×60 = 120 km/hour
A train traveled at an average speed of 100 km/hr, stopping for 3 minutes after every 75 km. How long did it take to reach its destination 600 km from the starting point.
Time taken to cover 600 km = 6 hours [because train speed is 100 km/hr]
Number of stops =
begin{aligned}
frac{600}{75} - 1 = 7 \
text{Total time on stops =}7×3 = 21 mins
end{aligned}
Total time taken by train = 6 hours 21 mins
A person travels equal distances with speed of 3 km/hr, 4 km/hr and 5 km/hr and takes a total of 47 minutes. Find the total distane
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