Challenging questions in the Quantitative Section may 
        test your ability to cut through dense information to get to the heart 
        of what often turns out to be a relatively simple matter. Why does the 
        Exam do this? To see whether you have the ability to whittle complex language 
        down to an easy solution. In these problems, the important thing is to 
        find the "question behind the question." That is, to find what 
        the question is really asking. Here’s an example:
                At the end of every hour a culture of bacteria becomes some 
                  number of times larger than it was the previous hour. If the 
                  number of bacteria was originally greater than 1 and if the 
                  rate of growth also increases every hour, what was the original 
                  number of bacteria?
                  1)  of 
                    the original culture would have resulted in a total of 385 
                    bacteria after 3 hours.
of 
                    the original culture would have resulted in a total of 385 
                    bacteria after 3 hours.
                  2)	The original number of bacteria was less than 4.
                
                This problem is really about  
                
                  . 
          
                      1)  of 
                        the original culture would have resulted in a total of 
                        385 bacteria after 3 hours.?
of 
                        the original culture would have resulted in a total of 
                        385 bacteria after 3 hours.?
                   
                 
                  |  |  | Sufficient |  | Insufficient |  |  | 
         
    Countinue 
 
      What does this mean? Well, if  of the original culture would’ve 
        resulted in 385 bacteria after 3 hours, then the actual number of bacteria 
        must equal 1155 after 3 hours. If we look at this as an equation, we get
 of the original culture would’ve 
        resulted in 385 bacteria after 3 hours, then the actual number of bacteria 
        must equal 1155 after 3 hours. If we look at this as an equation, we get 
         . So if we multiply both sides by 3, to get rid of the 
        fraction, we get cbax = 1155. The product 1155 should set off a 
        prime factorization alarm, since it contains some primes as factors (most 
        clearly 5 and 11).
. So if we multiply both sides by 3, to get rid of the 
        fraction, we get cbax = 1155. The product 1155 should set off a 
        prime factorization alarm, since it contains some primes as factors (most 
        clearly 5 and 11).
      If we divide 1155 by 11, we get 11  × 105, 
        which gives us 11 × 
        5 ×   21, which 
        gives us 11 ×  
        5 ×  7 × 
        3. So the prime factorization of 1155 is 3 ×   
        5 ×  7 × 
        11. But this is insufficient to tell us which of these numbers is the 
        original number of bacteria.
      We know that the three hourly rates of increase have to be in 
        increasing size order, but there are four ways to start with one of these 
        numbers as the original number and the other three as the increasing 
        rates of growth: 3 ×  
        5 ×  7 × 
        11 or 5 × 
        3 ×  7 ×  
        11 or 7 × 
        3 ×  5 ×  
        11 or 11 ×  
        3 ×  5 × 
        7. So Statement (1) is insufficient to tell us what the original number 
        of bacteria was.
      Now let’s look at Statement (2).
  
        
         Countinue
     
    
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