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6897 is divisible by
The greatest number by which the product of three consecutive multiples of 3 is always
What least number must be subtracted from 427398 so that remaining number is divisible by 15
A number when divided by the sum of 555 and 445 gives two times their difference as quotient and 30 as remainder. The number is
The greatest number of four digits which is divisible by 15, 25, 40, 75 is
We want 4 digits number, so option A is not the answer
Now, we want greater number. So out of remaining option, 9600 is greatest
9600 is divisible by 25, 75, 45 and 15
So option C is i.e. 9600
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