Lesson: Geometry - 29t01

Finding The Area Of Quadrilaterals

[Page 29 of 30]

See if you can apply what you've just learned to the following question. Select an answer and then click continue.

In the diagram, the blue region is a square with an area of 25. If EH has a length twice that of IH, and HG has a length four times that of HK, then what is the perimeter of rectangle EFGH?

	60
	130
	200
	270
	340

Countinue

The area of a square is a side times a side, or s ². We are given the area which we can then use to find the sides IH and HK:

Since the length of the rectangle is 4 times the side, it equals 20. Since the width of the rectangle is 2 times the side, it equals 10. The perimeter of the rectangle is therefore 2(20)+2(10)=60.

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Lesson: Geometry - 29t01

Finding The Area Of Quadrilaterals

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Lesson: Geometry - 29t01

Finding The Area Of Quadrilaterals

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