A box contains 3 blue marbles, 2 green marbles,
and 4 red marbles. If one marble is selected at random, and
a second marble is selected without replacing the first, what
is the probability that both marbles chosen are blue?
|
 |
What is the probability that a blue
marble will be chosen on the first draw? Enter your response into
the text box below and then click Continue. |
Probability of blue on 1st draw:
|
 |
What is the probability that a blue
marble will be chosen on the second draw if a blue marble was chosen
on the first draw? Enter your response into the text box below and
then click Continue. |
Probability of blue on 2nd draw:
|
 |
Now compute the probability that
BOTH the first and second marbles drawn will be blue. |
 |
Now use our sample question to determine
the probability for each of the two scenarios that follow. For each
one, enter your response into the textbox and then click Continue. |
There are 4 red marbles out of a total of 9,
so the probability of choosing green on the first draw is:
.
If one red marble has been taken out and not
replaced, we now have 8 marbles from which to choose. However, no green
marble has been removed, so we have our original number of green marbles
from which to select. Therefore, the probability of choosing green on
the second draw is:
.
The combined probability for the draws is:
.
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Video Lessons and 10 Fully Explained Grand Tests
Large number of solved practice MCQ with explanations. Video Lessons and 10 Fully explained Grand/Full Tests.